DJing Discussion
ms. wipe me down
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ms. wipe me down
dj cubicle
8:03 PM - 7 June, 2007
j;43lk6q;j4l vparvth-98 sd-98grf7uqh- 3yt6vqb3lk4jctl glholvahbcafljbsl tqj ybv30 azbjva
dj skraps
8:18 PM - 7 June, 2007
i saw there was a melissa on here...i hope some dude dont go by melissa
allenbina
6:17 AM - 8 June, 2007
head, shoulders knees and toes, knees and toes
Quote:
shoulders chest legs shoeshead, shoulders knees and toes, knees and toes
s42000
6:54 PM - 8 June, 2007
The displacement y is the amplitude of the waveSometimes this distance is called the peak amplitude, distinguishing it from another concept of amplitude, used especially in electrical engineering: the RMS or root mean square amplitude, defined as the square root of the temporal mean of the square of the vertical distance of this graph from the horizontal axis. The use of peak amplitude is unambiguous for symmetric, periodic waves, like a sine wave, a square wave, or a triangular wave. For an asymmetric wave (periodic pulses in one direction, for example), the peak amplitude becomes ambiguous because the value obtained is different depending on whether the maximum positive signal is measured relative to the mean, the maximum negative signal is measured relative to the mean, or the maximum positive signal is measured relative the maximum negative signal (the peak-to-peak amplitude) and then divided by two.
shiestO!
7:01 PM - 8 June, 2007
he just mathematically proved it. all dudes. it's a swordfight.
Quote:
The displacement y is the amplitude of the waveSometimes this distance is called the peak amplitude, distinguishing it from another concept of amplitude, used especially in electrical engineering: the RMS or root mean square amplitude, defined as the square root of the temporal mean of the square of the vertical distance of this graph from the horizontal axis. The use of peak amplitude is unambiguous for symmetric, periodic waves, like a sine wave, a square wave, or a triangular wave. For an asymmetric wave (periodic pulses in one direction, for example), the peak amplitude becomes ambiguous because the value obtained is different depending on whether the maximum positive signal is measured relative to the mean, the maximum negative signal is measured relative to the mean, or the maximum positive signal is measured relative the maximum negative signal (the peak-to-peak amplitude) and then divided by two.he just mathematically proved it. all dudes. it's a swordfight.
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